$newDt = Date.AddDay
("<date>", <n>)
Adds or subtracts n days to the specified date.
Parameters
<date> Any valid date expression in dd/mm/yyyy format.
<n> Number of days as a positive or negative integer.
Return Value
Example
$sdate = "20/11/2005"
$ret = date.AddDay ($sdate, 5)
- $ret contains 25/11/2005.